Steps to draw graph of y=ax2+bx+c as follows:
Draw graph of equation y=x2-4x-5
- Determine absis intersection, y = 0
- Determine ordinat intersection, x = 0
- Determine equation of axis of symmetry, x = -b/2a
- Determine maximum or minimum value, y = (b2-4ac)/4a
- Determine coordinate of extreme point, (x,y) = (-b/2a,(b2-4ac)/4a)
- If 5 steps above have not drawn parabola sketch yet, then get some auxiliary point
Draw graph of equation y=x2-4x-5
- Determine absis intersectiony = 0 then:
y = x2-4x-5
(x-5) (x+1) = 0
x1 = -1 dan x2 = 5
then absis intersection are (-1,0) dan (5,0)
- Determine ordinat intersection
x = 0 then:
y = 02-4(0)-5
y = -5
then ordinat intersection is (0,-5)
- Determine equation of axis of symmetry
x = -b/2a
x = -(-4)/2(1)
x = 2
axis of symmetry is line x = 2
- Determine maximum or minimum value
y = (b2-4ac)/-4a
y = ((-4)2-4(1)(-5))/-4(1)
y = -9
- Extreme pointk:
(-b/2a,(b2-4ac)/4a)
(-(-4)/2(1),((-4)2-4(1)(-5)/4(1))
(4/2,36/4)
(2,9)
- Connect points are gotten
Sumber :sahabat-informasi
Penyusun : D-0322/kelas A/IAIN-Mtrm
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